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C++高精度运算
阅读量:686 次
发布时间:2019-03-17

本文共 1647 字,大约阅读时间需要 5 分钟。

  1. 高精度加法
vector
add(vector
&A, vector
&B){ vector
C; int t = 0; for(int i = 0; i < A.size() || i < B.size(); i++) { if(i < A.size()) t += A[i]; if(i < B.size()) t += B[i]; C.push_back(t % 10); t /= 10; } if(t) C.push_back(1); return C;}
  1. 高精度减法
//判断A B 的大小, 保证函数里面是大的减小的bool cmp(vector
&A, vector
&B){ if(A.size() != B.size()) return A.size() > B.size(); for(int i = A.size() - 1; i >= 0; i--) if(A[i] != B[i]) return A[i] > B[i]; return true; }vector
add(vector
&A, vector
&B){ vector
C; int t = 0; for(int i = 0; i < A.size() ; i++) { t = A[i] - t; if(i < B.size()) t = t - B[i]; C.push_back((t + 10) % 10); if(t < 0) t = 1; else t = 0; } while(C.size() > 1 && C.back() == 0) C.pop_back(); return C;}

3.高精度乘低精度

vector
mul(vector
&A, int b){ vector
C; int t = 0; for(int i = 0; i < A.size(); i++){ t += b * A[i]; C.push_back(t % 10); t /= 10; } if(t) C.push_back(t); /* 如果这里b是>10的数, 就写成 while(t){ C.push_back(t % 10); t /= 10; } */ return C;}

4.高精度除低精度

A除b余rvector
div(vector
&A, int b, int &r){ vector
C; int t = 0; for(int i = A.size() - 1; i >= 0; i--){ t *= 10; t += A[i]; C.push_back(t / b); t %= b; } r = t; reverse(C.begin(), C.end()); while(C.size() > 1 && C.back() == 0) C.pop_back(); return C;}

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